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00:00 - 00:59 | hello friends Mera question is in the given figure a square oabc is inscribed in a quadrant of a circle if a is equal to 21 CM then find the area of the shaded region so according to our question we have the figure op is the quadrant and a square oabc is inscribed in this quadrant so area of shaded season is equal to area of quadrant minus area of care and now we have to find the area of square |

01:00 - 01:59 | as you know that the formula for area of square is side X side and going to have a question is equal to 21 CM that is 21 multiply 21 which is equal to 44128 if we draw the diagonal if we draw the diagonal of B then diagonal of square is equal to under root 2 X side means a under to multiply 21 that is equal to 21 under root 2 cm and diagonal of square |

02:00 - 02:59 | is equal to radius of circle and hence the area of quadrant is equal to 1 / 45 are here and now we calculate area of water that is 1 / 4 multiply 22/7 multiply and this is also equal to radius is 21 under root 2 cm this is 21 under root 2 X 21 under root 2 that is equal to 1 / 4 multiply 22 / |

03:00 - 03:59 | multiply 441 multiplied to that is world to 693 CM square so area of shaded region is area of quadrant - area of sphere sunao calculate the area of shaded region area of shaded region is equal to area of quadrant is 693 CM square minus and area of square is 441 CM here so here it is equal to 252 care so this is our |

04:00 - 04:59 | area of this shaded portion answer thank you |